0=(-2(x^-3))-(4(x^-1.5))

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Solution for 0=(-2(x^-3))-(4(x^-1.5)) equation:



0=(-2(x^-3))-(4(x^-1.5))
We move all terms to the left:
0-((-2(x^-3))-(4(x^-1.5)))=0
We add all the numbers together, and all the variables
-((-2(x^-3))-(4(x^-1.5)))=0
We calculate terms in parentheses: -((-2(x^-3))-(4(x^-1.5))), so:
(-2(x^-3))-(4(x^-1.5))
We calculate terms in parentheses: +(-2(x^-3)), so:
-2(x^-3)
We multiply parentheses
-2x+6
Back to the equation:
+(-2x+6)
We calculate terms in parentheses: -(4(x^-1.5)), so:
4(x^-1.5)
We multiply parentheses
4x-6
Back to the equation:
-(4x-6)
We get rid of parentheses
-2x-4x+6+6
We add all the numbers together, and all the variables
-6x+12
Back to the equation:
-(-6x+12)
We get rid of parentheses
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2

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